Sum
A cylinderical container with diameter of base 42 cm contains sufficient water to submerge a rectangular soild of iron with dimesions 22cm xx14 cm 10.5cm. find the rise in level of the water the solid is submerged.
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Solution
`"Diameter of cylindrical container"=42 cm`
`"Therefore, radius (r)"=21 cm `
`"Dimensions of reactangular solid" =22 cmxx14 cmxx10.5 cm`
`"Volume of solid"=22x14xx10.5 cm^3`
`"Let height of water"=h`
`"Therefore, volume of water in the container"=pir^2h`
`=22/7xx21xx21xxh cm^3=22xx63h cm^3...........(2)`
From (1) and (2)
`22xx63h=22xx14xx10.5`
`⇒ h=(22xx14xx10.5)/(22xx63)`
`⇒ h=7/3`
`⇒h=2 1/3 or 2.33 cm`
Concept: Volume of a Cylinder
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