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A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of toys produced in a day. On a particular day, the total cost of production was Rs 750. We would like to find out the number of toys produced on that day.
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Solution
Let the number of toys produced be x.
∴ Cost of production of each toy = Rs (55 - x)
It is given that, total production of the toys = Rs 750
∴ x(55 - x) = 750
⇒ x2 – 55x + 750 = 0
⇒ x2 – 25x - 30x + 750 = 0
⇒ x(x - 25) -30(x - 25) = 0
⇒ (x - 25)(x - 30) = 0
Either, x -25 = 0 or x - 30 = 0
⇒ x = 25 or x = 30
Hence, the number of toys will be either 25 or 30.
Concept: Solutions of Quadratic Equations by Factorization
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