A converging mirror forms a real image of height 4 cm of an object of height 1 cm placed 20 cm away from the mirror:
(i) Calculate the image distance.
(ii) What is the focal length of the mirror?
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Solution
A concave mirror is a converging mirror.
Distance of the object from the mirror 'u' = -20 cm
Height of the object 'ho' = 1 cm
Height of the image 'hi' = -4 cm
We have to find the distance of the image 'v' and focal length of the mirror 'f'.
We have to find the distance of the image 'v' and focal length of the mirror 'f'.
Using the magnification formula, we get
`m=h_i/h_o=-v/u`
`-4/1=-v/-20`
`v=20xx-4/1=-80` cm
Thus, the distance of the image 'v' is 80 cm.
Now, using the mirror formula, we get
`1/f=1/v+1/u`
`1/f=1/-80+1/-20=-1/80-4/80=-5/80`
`1/f=-1/16`
f=-16 cm
Thus, the focal length of the concave mirror is 16 cm.
Concept: Concave Mirror
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