A conical tent is 10 m high and the radius of its base is 24 m. Find

(i) slant height of the tent

(ii) cost of the canvas required to make the tent, if the cost of 1 m^{2} canvas is Rs 70.

`["Assume "pi=22/7]`

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#### Solution

(i) Let ABC be a conical tent.

Height (*h*) of conical tent = 10 m

Radius (*r*) of conical tent = 24 m

Let the slant height of the tent be *l*.

In ΔABO,

AB^{2} = AO^{2} + BO^{2}

*l*^{2} = *h*^{2} +* r*^{2}

= (10 m)^{2} + (24 m)^{2}

= 676 m^{2}

∴ *l* = 26 m

Therefore, the slant height of the tent is 26 m.

(ii) CSA of tent = π*rl*

`=(22/7xx24xx26)m^2`

`=13728/7m^2`

Cost of 1 m^{2} canvas = Rs 70

`"Cost of "13728/7m^2" canvas "=Rs.(13728/7xx70)`

= Rs. 137280

Therefore, the cost of the canvas required to make such a tent is Rs 137280.

Is there an error in this question or solution?

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