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Numerical
A conductor of linear mass density 0.2 g m1 suspended by two flexible wire as shown in figure. Suppose the tension in the supporting wires is zero when it is kept inside the magnetic field of I T whose direction is into the page. Compute the current inside the conductor and also the direction for the current. Assume g = 10 m s-2.
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Solution
Downward force, F = mg
Linear mass density, `m/l` = 0.2 gm-1
`m/l` = 0.2 x 10-3 kg m-1
m = (0.2 x 10-3 x l) kg m-1
F = (0.2 x 10-3 x l x 10) N
Upward magnetic force acting on the wire
F = BIl
0.2 x 10-3 x l x 10 = 1 x I x l
I = 2 x 10-3
I = 2 m A
Concept: Magnetic Effects of Current
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