Department of Pre-University Education, Karnataka course PUC Karnataka Science Class 12
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# A Conducting Square Loop Having Edges of Length 2.0 Cm is Rotated Through 180° About a Diagonal in 0.20 S. - Physics

ConceptElectromagnetic Induction Questions

#### Question

A conducting square loop having edges of length 2.0 cm is rotated through 180° about a diagonal in 0.20 s. A magnetic field B exists in the region which is perpendicular to the loop in its initial position. If the average induced emf during the rotation is 20 mV, find the magnitude of the magnetic field.

#### Solution

Given:-

Induced emf, e = 20 mV = 20 × 10−3 V

Area of the loop, A = (2 × 10−2)2 = 4 × 10−4 m2

Time taken to rotate the loop, Δt = 0.2 s

The average induced emf is given by

$e = - \frac{∆ \phi}{∆ t} = \frac{\phi_i - \phi_f}{t}$

$\phi = \overrightarrow{B} . \overrightarrow{A} = BA\cos\theta$

$\phi_i = B(4 \times {10}^{- 4} )\cos0 = B(4 \times {10}^{- 4} )$

$\phi_f = B(4 \times {10}^{- 4} )\cos {180}^o = - B(4 \times {10}^{- 4} )$

$e = \frac{B(4 \times {10}^{- 4} ) - \left[ - B(4 \times {10}^{- 4} ) \right]}{0 . 2}$

$20 \times {10}^{- 3} = \frac{8B \times {10}^{- 4}}{2 \times {10}^{- 1}}$

$\Rightarrow 20 \times {10}^{- 3} = 4 \times B \times {10}^{- 3}$

$\Rightarrow B = \frac{20 \times {10}^{- 3}}{4 \times {10}^{- 3}} = 5 T$

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#### APPEARS IN

Solution A Conducting Square Loop Having Edges of Length 2.0 Cm is Rotated Through 180° About a Diagonal in 0.20 S. Concept: Electromagnetic Induction Questions.
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