Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12
Advertisement Remove all ads

A Concave Mirror Having a Radius of Curvature 40 Cm is Placed in Front of an Illuminated Point Source at a Distance of 30 Cm from It. Find the Location of the Image. - Physics

Sum

A concave mirror having a radius of curvature 40 cm is placed in front of an illuminated point source at a distance of 30 cm from it. Find the location of the image.

Advertisement Remove all ads

Solution

Using sign conventions, given,
Distance of object from mirror, u = − 30 cm,
Radius of curvature of concave mirror R = − 40 cm

Using the mirror equation,

\[\frac{1}{v} + \frac{1}{u} = \frac{2}{R}\] 

\[ \Rightarrow   \frac{1}{v} = \frac{2}{R} - \frac{1}{u}\] 

\[ \Rightarrow \frac{1}{v} = \frac{2}{- 40} - \frac{1}{- 30} = \frac{1}{- 20} + \frac{1}{30}\] 

\[ \Rightarrow \frac{1}{v} = \frac{- 30 + 20}{30 \times 20} = \frac{- 10}{30 \times 20}\] 

\[ \Rightarrow \frac{1}{v} =  - \frac{1}{60}\]

or, v = − 60 cm
Hence, the required image will be located at a distance of 60 cm in front of the concave mirror.

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

HC Verma Class 11, 12 Concepts of Physics 1
Chapter 18 Geometrical Optics
Q 1 | Page 412
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×