Maharashtra State BoardHSC Arts 12th Board Exam
Advertisement Remove all ads

A company produces two types of articles A and B which require silver and gold. Each unit of A requires 3 gm of silver and 1 gm of gold, while each unit of B requires 2 gm of silver and 2 gm of gold. - Mathematics and Statistics

Sum

A company produces two types of articles A and B which require silver and gold. Each unit of A requires 3 gm of silver and 1 gm of gold, while each unit of B requires 2 gm of silver and 2 gm of gold. The company has 6 gm of silver and 4 gm of gold. Construct the inequations and find feasible solution graphically

Advertisement Remove all ads

Solution

Let the company produces x units of article A and y units of article B.
The given data can be tabulated as:

  Article A
(x)

Article B
(y)

Availability
Gold 1 2 4
Silver 3 2 6

Inequations are:

x + 2y ≤ 4 and 3x + 2y ≤ 6

x and y are number of items, x ≥ 0, y ≥ 0

First we draw the lines AB and CD whose equations are x + 2y = 4 and 3x + 2y = 6 respectively.

Line Equation Points on the X-axis Points on the Y-axis Sign Region
AB x +2y = 4 A(4, 0) B(0, 2) origin side of line AB
CD 3x + 2y = 6 C(2, 0) D(0, 3) origin side of line CD

The feasible solution is OCPBO which is shaded in the graph.

Concept: Linear Programming Problem (L.P.P.)
  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×