A company produces two types of articles A and B which require silver and gold. Each unit of A requires 3 gm of silver and 1 gm of gold, while each unit of B requires 2 gm of silver and 2 gm of gold. The company has 6 gm of silver and 4 gm of gold. Construct the inequations and find feasible solution graphically
Let the company produces x units of article A and y units of article B.
The given data can be tabulated as:
x + 2y ≤ 4 and 3x + 2y ≤ 6
x and y are number of items, x ≥ 0, y ≥ 0
First we draw the lines AB and CD whose equations are x + 2y = 4 and 3x + 2y = 6 respectively.
|Line||Equation||Points on the X-axis||Points on the Y-axis||Sign||Region|
|AB||x +2y = 4||A(4, 0)||B(0, 2)||≤||origin side of line AB|
|CD||3x + 2y = 6||C(2, 0)||D(0, 3)||≤||origin side of line CD|
The feasible solution is OCPBO which is shaded in the graph.