A company produces two types of articles A and B which require silver and gold. Each unit of A requires 3 gm of silver and 1 gm of gold, while each unit of B requires 2 gm of silver and 2 gm of gold. - Mathematics and Statistics

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Sum

A company produces two types of articles A and B which require silver and gold. Each unit of A requires 3 gm of silver and 1 gm of gold, while each unit of B requires 2 gm of silver and 2 gm of gold. The company has 6 gm of silver and 4 gm of gold. Construct the inequations and find feasible solution graphically

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Solution

Let the company produces x units of article A and y units of article B.
The given data can be tabulated as:

  Article A
(x)

Article B
(y)

Availability
Gold 1 2 4
Silver 3 2 6

Inequations are:

x + 2y ≤ 4 and 3x + 2y ≤ 6

x and y are number of items, x ≥ 0, y ≥ 0

First we draw the lines AB and CD whose equations are x + 2y = 4 and 3x + 2y = 6 respectively.

Line Equation Points on the X-axis Points on the Y-axis Sign Region
AB x +2y = 4 A(4, 0) B(0, 2) origin side of line AB
CD 3x + 2y = 6 C(2, 0) D(0, 3) origin side of line CD

The feasible solution is OCPBO which is shaded in the graph.

Concept: Linear Programming Problem (L.P.P.)
  Is there an error in this question or solution?
Chapter 7: Linear Programming - Exercise 7.2 [Page 234]

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