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Sum
A coin is tossed twice. Find the probability of getting: exactly one tail
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Solution
Exactly one tail
Possible number of favourable outcomes = 2 (i.e. TH and HT)
Total number of possible outcomes = 4
∴ P(E) = `"Number of favourable outcomes"/"Total number of possible outcomes"`
= `2/4 = 1/2`
Concept: Basic Ideas of Probability
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