Question

A clock regulated by seconds pendulum, keeps correct time. During summer, length of pendulum increases to 1.005 m. How much will the clock gain or loose in one day?

(g = 9.8 m/s² and π = 3.142)

Answer 1

Given: L = 1.005 m, g = 9.8 m/s²

To find: Loss in period (ΔT)

Formula: `T=2pisqrt(L/g)`

`T=2xx3.14xxsqrt(1.005/9.8)`

`=2.012 s`

The period of a seconds pendulum is 2 second.
Hence, the given pendulum clock will lose 0.012s in 2.012s (during summer).
Loss in period per day

`ΔT=(24xx3600xx0.012)/2.012`

`DeltaT=515.3s`

The clock will gain or lose 515.3 s in one day.