Sum

A classroom has dimension 10×8×6m^{3}. the reverberation time is 3 sec. calculate the total absorption of surface and average absorption.

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#### Solution

Given Data :- V = 10×8×6 = 480m^{3 }

S = 2[(10×8) + (8×6) + (10×6)] = 376 m^{3}

T = 3 sec.

Formula :-` T = 0.161V/A = 0.161V/(α_(av).S)`

Calculations:- `A =( 0.161×V)/T =(0.161×480)/3 = 25.76 " sabine" -m^2`

`α_(av) = A/S =(25.76)/(376)= 0.068 ` sabine.

Answer :- Total absorption , A = 25.76 sabine-m^{2 }

Average absorption coefficient, α_{av } = 0.068 sabine

Concept: Reflection of Sound(Reverberation and Echo)

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