A circular coil of cross-sectional area 200 cm^{2} and 20 turns is rotated about the vertical diameter with angular speed of 50 rad s^{−1} in a uniform magnetic field of magnitude 3.0 × 10^{−2}T. Calculate the maximum value of the current in the coil.

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#### Solution

Here, A = 200 cm^{2}

N=20

ω = 50 rad/s

B = 3.0× 10^{−2} T

for maximum current emf induced should be maximum.

So, for maximum emf sinωt in e = NAB ω sinωt should be 1.

Hence, e = NABω

`e = 20 × 200/10000 × 50 × 3 × 10^-2 `

`e= 0.6 V`

Since, resistance of the circular loop is not given, let us consider its resistance to be R.

Therefore, current I in the coil is

`I = 0.6/R A`

Concept: Electromagnetic Induction Questions

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