#### Question

MCQ

A child was born on 13th January 1976 which was a Tuesday. What day of the week will be the child‘s birthday in the year 1986?

#### Options

Sunday

Friday

Saturday

Monday

#### Solution

**Monday**

**Explanation:**

We know that,

Number of odd days in a non-leap year = 1

Number of odd days in a Leap year = 2

As year 1976 is a leap year.

So, Number of odd day in 1976 = 2

Similarly, 1980, 1984 are two leap year.

between 1976 to 1986

Also, Number of non-leap year between 1976 to 1986 = 7 year

Total number of odd days

= 3 × 2 + 7 × 1 = 13 days

13 days = 1 week + 6 days

Hence, 13th January 1986 will be Monday.

Concept: Probability (Entrance Exam)

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