# A cell constituted by two electrodes A (EAAEA+/A0 = 0.35 V) and B (EBBEB+/B0 = + 0.42 V) has value of EcellEcell0 equal to _________. - Chemistry

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A cell constituted by two electrodes A ("E"_("A"^+//"A")^0 = 0.35 V) and B ("E"_("B"^+//"B")^0 = + 0.42 V) has value of "E"_"cell"^0 equal to _________.

• 0.77 V

• 0.07 V

• –0.77 V

• –0.07 V

#### Solution

A cell constituted by two electrodes A ("E"_("A"^+//"A")^0 = 0.35 V) and B ("E"_("B"^+//"B")^0= + 0.42 V) has a value of "E"_"cell"^0 equal to 0.07 V.

Explanation:

The species which has lesser value of standard reduction potential (E0) is better reducing agent.

A ⇒ Reducing agent = it will undergo oxidation = Anode

B ⇒ Oxidising agent = it will undergo reduction = Cathode

"E"_"cell"^0 = "E"_"cathode"^0 - "E"_"anode"^0

"E"_"cell"^0 = + 0.42 " V" - 0.35 " V"

"E"_"cell"^0 = 0.07 V

Concept: Electrolytic Cell
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Chapter 5: Electrochemistry - Multiple choice questions

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SCERT Maharashtra Question Bank 12th Standard HSC Chemistry Maharashtra State Board
Chapter 5 Electrochemistry
Multiple choice questions | Q 9
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