Answer 1

Let S denote the sample space.
Then, n(S) = 52

 Let E₁ = event of drawing a black king
    We know that the number of black kings is two: one for spade and one for club.
     i.e. n (E₁) = 2

\[\therefore P\left( E_1 \right) = \frac{n\left( E_1 \right)}{n\left( S \right)} = \frac{2}{52} = \frac{1}{26}\]