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A Car is Moving with a Uniform Velocity 30 Ms-1. It is Stopped in 2 S by Applying a Force of 1500 N Through Its Brakes. Calculate the Following Values : the Retardation Produced in Car. - Physics

Sum

A car is moving with a uniform velocity 30 ms-1. It is stopped in 2 s by applying a force of 1500 N through its brakes. Calculate the following values :  The retardation produced in car.

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Solution

Initial velocity, u = 30 m/s

Final velocity, v = 0

Time, t = 2s

Force, F = 1500 N

Here, a = (v - u)/t = (0 - 30)/ 2 = - 15 ms-2. Here, negative sign indicates retardation.

Now, F = ma.

Or, m = F/a = (1500/ 15) = 100 kg.

Acceleration, a = (v-u)/t.

Or, a = (0 - 30)/ 2 = -15 ms-2,

Here, negative sign indicates retardation.

Thus, retardation = 15 ms-2.

Concept: Free Fall
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APPEARS IN

Selina Concise Physics Class 9 ICSE
Chapter 3 Laws of Motion
Exercise 3 (C) | Q 13.2 | Page 70
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