Advertisement Remove all ads

A Business Man Hosts a Dinner to 21 Guests. He is Having 2 Round Tables Which Can Accommodate 15 and 6 Persons Each. in How Many Ways Can He Arrange the Guests? - Mathematics

A business man hosts a dinner to 21 guests. He is having 2 round tables which can accommodate 15 and 6 persons each. In how many ways can he arrange the guests?

Advertisement Remove all ads

Solution

A businessman hosts a dinner for 21 guests.
15 people can be accommodated at one table in 21C15 ways. They can arrange themselves in \[\left( 15 - 1 \right)! = 14!\]ways.
The remaining 6 people can be accommodated at another table in 6C6 ways. They can arrange themselves in\[\left( 6 - 1 \right)! = 5!\]  ways.
∴ Total number of ways =\[{}^{21} C_{15} \times^6 C_6 \times 14! \times 5! =^{21} C_{15} \times 14! \times 5!\]

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 17 Combinations
Exercise 17.3 | Q 9 | Page 23
Advertisement Remove all ads

Video TutorialsVIEW ALL [1]

Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×