A bus starting from rest moves with a uniform acceleration of 0.1 m s^{−2} for 2 minutes. Find (a) the speed acquired, (b) the distance travelled.

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#### Solution

(a) Initial speed of the bus, *u* = 0 (since the bus is initially at rest)

Acceleration, *a* = 0.1 m/s^{2}

Time taken, *t* = 2 minutes = 120 s

Let *v* be the final speed acquired by the bus.

`therefore a =(v-u)/t`

`0.1 =(v-0)/120`

∴*v* = 12 m/s

(b) According to the third equation of motion:

*v*^{2} − *u*^{2} = 2*as*

Where, *s* is the distance covered by the bus

(12)^{2} − (0)^{2} = 2(0.1) *s*

*s *= 720 m

Speed acquired by the bus is 12 m/s.

Distance travelled by the bus is 720 m.

Concept: Equations of Motion by Graphical Method - Derivation of Position - Time Relation by Graphical Method

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