# A bullet going with speed 350 m/s enters a concrete wall and penetrates a distance of 5.0 cm before coming to rest. Find the deceleration. - Physics

Short Note

A bullet going with speed 350 m/s enters a concrete wall and penetrates a distance of 5.0 cm before coming to rest. Find the deceleration.

#### Solution

Initial velocity, = 350 m/s
Final velocity, v = 0
Distance travelled by the bullet before coming to rest, s = 5 m

$\text{ Acceleration, a } = \frac{v^2 - u^2}{2s}$

$\Rightarrow a = \frac{0 - \left( 350 \right)^2}{2 \times 0 . 05} = - 12 . 2 \times {10}^5 \text{ m } / s^2$

∴ Deceleration = 12.2 × 105 m/s2

Is there an error in this question or solution?

#### APPEARS IN

HC Verma Class 11, 12 Concepts of Physics 1
Chapter 3 Rest and Motion: Kinematics
Q 17 | Page 52