Maharashtra State BoardHSC Science (General) 11th
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A box contains 75 tickets numbered 1 to 75. A ticket is drawn at random from the box. Find the probability that, Number on the ticket is divisible by 3 and 5 - Mathematics and Statistics

Sum

A box contains 75 tickets numbered 1 to 75. A ticket is drawn at random from the box. Find the probability that, Number on the ticket is divisible by 3 and 5

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Solution

The box contains 75 tickets numbered 1 to 75.

∴ 1 ticket can be drawn from the box in 75C1 = 75 ways.

∴ n(S) = 75

Let event D: Number on the ticket is divisible by 3 and 5, i.e., divisible by L.C.M. of 3 and 5, i.e.,15.

∴ D = {15, 30, 45, 60, 75}

∴ n(D) = 5

∴ P(D) = `("n"("D"))/("n"("S"))`

= `5/75`

= `1/15`

Concept: Basic Terminologies
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