MCQ
A box contains 10 good articles and 6 with defects. One item is drawn at random. The probability that it is either good or has a defect is
Options
64/64
49/64
40/64
24/64
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Solution
\[\frac{64}{64}\]
Let A be the event of drawing one good article whereas B be the event of drawing one defected article.
Here,
\[P\left( A \right) = \frac{10}{10 + 6} = \frac{10}{16} \text{ and } P\left( B \right) = \frac{6}{10 + 6} = \frac{6}{16}\]
The events A and B are mutually exclusive. Thus, the required probability is \[P\left( A \cup B \right) = P\left( A \right) + P\left( B \right)\]
\[\Rightarrow P\left( A \cup B \right) = \frac{10}{16} + \frac{6}{16} = \frac{16}{16} = 1\]
Concept: Probability - Probability of 'Not', 'And' and 'Or' Events
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