Advertisement Remove all ads

# A body weighs 5.6 kg-wt on the surface of the Earth. How much will be its weight on a planet whose mass is 1/7th mass of the Earth and radius twice that of the Earth’s radius? - Physics

Sum

Solve the following problem.

A body weighs 5.6 kg-wt on the surface of the Earth. How much will be its weight on a planet whose mass is 1/7th mass of the Earth and radius twice that of the Earth’s radius?

Advertisement Remove all ads

#### Solution

Given: WE = 5.6 kg-wt., "M"_"p"/"M"_"E" = 1/7, "R"_"p"/"R"_"E" = 2

To find: Weight of the body on the surface of the planet (Wp)

Formula: W = mg = "GMm"/"R"^2

Calculation: From formula,

"W"_"p"/"W"_"E" = "M"_"p"/"M"_"E" xx "R"_"E"^2/"R"_"p"^2

"W"_"p"/5.6 = 1/7 xx (1/2)^2 = 1/28

∴ "W"_"p" = 1/28 xx 5.6 = 0.2 kg-wt.

Weight of the body on the surface of a planet will be 0.2 kg-wt.

Concept: Earth Satellites
Is there an error in this question or solution?
Advertisement Remove all ads

#### APPEARS IN

Balbharati Physics 11th Standard Maharashtra State Board
Chapter 5 Gravitation
Exercises | Q 4. (xi) | Page 99
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications

Forgot password?