Answer 1

m = 1 kg, K = 16 N/m

ω = ?, n = ?

We have, for S.H.M.

ω = `sqrt(K/M)`

= `sqrt(16/1)`

∴ ω = 4 rad/s

Also, ω = 2πn

∴ n = `ω/(2pi)`

=  `4/(2pi) = 2/pi Hz`

∴ n = `2/3.14 = [log(2) - log(3.14)]`

= [0.3010 − 0.4969]

= antilog [1.8041]

= 0.6369

= 0.6369 Hz

The angular frequency of the body is 4 rad/s and the frequency of vibration is 0.6369 Hz.