Short Note

Sum

A body of 2 kg falls from rest. What will be its kinetic energy during the fall at the end of 2 s? (Assume g = 10 m/s^{2})

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#### Solution

Mass of the body, (m) = 2 kg

Initial velocity of the ball, (u) = 0 m/s

Time, (t) = 2s

Acceleration due to gravity, (g) = 10 m/s^{2}

Let the final velocity of the ball after 2 s be (v)

We know v = u + at

So, v = 0 + 10 (2) = 20 m/s

Now we can find the kinetic energy as:

Therefore,

`K.E = 1/2 (2)(20)^2 "J"`

= 400 J

So, the kinetic energy of the moving object is 400 J.

Is there an error in this question or solution?

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