Advertisement Remove all ads

A block of mass 7 kg and volume 0.07 m3 floats in a liquid of density 140 kg/m3. Calculate: Volume of block above the surface of liquid. Density of block. - Physics

Sum

A block of mass 7 kg and volume 0.07 m3 floats in a liquid of density 140 kg/m3. Calculate:

  1. Volume of block above the surface of liquid.
  2. Density of block.
Advertisement Remove all ads

Solution

Mass of block = m = 7 kg

Volume of block = V = 0.07 m3

Density of liquid =ρl = 140 kgm-3

Let V’ = Volume of block immersed in the liquid

By law of floatation:

Weight of block = Weight of liquid displaced by the immersed pa

`"V"'rho"g" = "V"'rho_l "g"`

`"V"' = rho/rho_l` V

Density of block = `rho = "m"/"V" = 7/0.07 = 100` kg m-3 

From (1)

`"V"' = (100 "V")/140 = 5/7 "V" = 5/7 xx 0.7`

`"V"' = 1/20 = 0.05` m3

Volume of block above the surface of liquid = V = V1 

= 0.07 - 0.05 = 0.02 m3 

Concept: Archimedes' Principle
  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

Goyal Brothers Prakashan Class 9 A New Approach to ICSE Physics Part 1
Chapter 5 Upthrust and Archimedes’ Principle
Subjective Questions | Q 5.2
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×