Answer 1

\[\text{ Mass of the block, M = 5 kg }\]
\[\text{ Angle of inclination } , \theta = 30^\circ\]

Gravitational force acting on the block,

\[F = mg\]

Work done by the force of gravity depends only on the height of the object, not on the path length covered by the object.

\[\text{ Height of the object , h }= 10 \times \sin30^\circ\]
\[ = 10 \times \frac{1}{2} = 5 m\]

\[\therefore \text{ Work done by the force of gravity, w = mgh } \]

\[ = 5 \times 9 . 8 \times 5 = 245 J\]