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A Block of Mass 5.0 Kg Slides Down an Incline of Inclination 30° and Length 10 M. Find the Work Done by the Force of Gravity. - Physics

Sum

A block of mass 5.0 kg slides down an incline of inclination 30° and length 10 m. Find the work done by the force of gravity.

 
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Solution

\[\text{ Mass of the block, M = 5 kg }\]
\[\text{ Angle of inclination } , \theta = 30^\circ\]

Gravitational force acting on the block,

\[F = mg\]
Work done by the force of gravity depends only on the height of the object, not on the path length covered by the object.
\[\text{ Height of the object , h }= 10 \times \sin30^\circ\]
\[ = 10 \times \frac{1}{2} = 5 m\]

\[\therefore \text{ Work done by the force of gravity, w = mgh } \]

\[ = 5 \times 9 . 8 \times 5 = 245 J\]

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APPEARS IN

HC Verma Class 11, 12 Concepts of Physics 1
Chapter 8 Work and Energy
Q 4 | Page 132
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