Question

A balloon vendor has 2 red, 3 blue and 4 green balloons. He wants to choose one of them at random to give it to Pranali. What is the probability of the event that Pranali gets, a red balloon

Answer 1

Given: 
Number of red baloon = 2
Number of blue baloon = 3
Number of green baloon = 4
Let S be the sample space.
∴ n(S) = Number of red baloon + Number of blue balloon + Number of green balloon 
= 2 + 3 + 4
= 9
 Let A be the event of getting a red balloon.
Given: n(A) = 2

`therefore P(A) = (n(A))/(n(S))`

`=2/9`

Hence, the probability of the event that Pranali gets a red baloon is `=2/9`.

Answer 2

Let the 2 red balloons be R₁, R₂, 3 blue balloons be B₁, B₂, B₃ and 4 green balloons be G₁, G₂, G₃, G₄.

∴ Sample space,

S = {R₁, R₂, B₁, B₂, B₃, G₁, G₂, G₃, G₄}

∴ n(S) = 9

Let A be the event that Pranali gets a red balloon.

∴ A = {R₁, R₂}

∴ n(A) = 2

∴ P(A) = `("n"("A"))/("n"("S"))`

∴ P(A) = `2/9`