Advertisement Remove all ads

A balloon vendor has 2 red, 3 blue and 4 green balloons. He wants to choose one of them at random to give it to Pranali. What is the probability of the event that Pranali gets, a red balloon - Algebra

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
Sum

A balloon vendor has 2 red, 3 blue and 4 green balloons. He wants to choose one of them at random to give it to Pranali. What is the probability of the event that Pranali gets, a red balloon

Advertisement Remove all ads

Solution 1

Given: 
Number of red baloon = 2
Number of blue baloon = 3
Number of green baloon = 4
Let S be the sample space.
∴ n(S) = Number of red baloon + Number of blue balloon + Number of green balloon 
= 2 + 3 + 4
= 9
 Let A be the event of getting a red balloon.
Given: n(A) = 2

`therefore P(A) = (n(A))/(n(S))`

`=2/9`

Hence, the probability of the event that Pranali gets a red baloon is `=2/9`.

Solution 2

Let the 2 red balloons be R1, R2, 3 blue balloons be B1, B2, B3 and 4 green balloons be G1, G2, G3, G4.

∴ Sample space,

S = {R1, R2, B1, B2, B3, G1, G2, G3, G4}

∴ n(S) = 9

Let A be the event that Pranali gets a red balloon.

∴ A = {R1, R2}

∴ n(A) = 2

∴ P(A) = `("n"("A"))/("n"("S"))`

∴ P(A) = `2/9`

Concept: Basic Ideas of Probability
  Is there an error in this question or solution?
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×