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A Balloon Vendor Has 2 Red, 3 Blue and 4 Green Balloons. He Wants to Choose One of Them at Random to Give It to Pranali. What is the Probability of the Event that Pranali Gets, a Blue Balloon - Algebra

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A balloon vendor has 2 red, 3 blue and 4 green balloons. He wants to choose one of them at random to give it to Pranali. What is the probability of the event that Pranali gets, a blue balloon

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Solution 1

Given:

Number of red baloon = 2

Number of blue baloon = 3

Number of green baloon = 4

Let S be the sample space.

∴ n(S) = Number of red baloon + Number of blue balloon + Number of green balloon 

= 2 + 3 + 4

= 9

Let B be the event of getting a blue balloon.

Given: n(B) = 3

`therefore  "P"("B") = ("n"("B"))/("n"("S"))`

= `3/9`

= `1/3`

Hence, the probability of the event that Pranali gets a blue baloon is `1/3.`

Solution 2

Let the 2 red balloons be R1, R2, 3 blue balloons be B1, B2, B3 and 4 green balloons be G1, G2, G3, G4.

∴ Sample space,

S = {R1, R2, B1, B2, B3, G1, G2, G3, G4}

∴ n(S) = 9

Let B be the event that Pranali gets a blue balloon

∴ B = {B1, B2, B3}

∴ n(B) = 3

∴ P(B) = `("n"("B"))/("n"("S"))`

= `3/9`

∴ P(B) = `1/3`

Concept: Basic Ideas of Probability
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