Answer in Brief

A ball X of mass 1 kg travelling at 2 m/s has a head-on collision with an identical ball Y at rest. X stops and Y moves off. Calculate the velocity of Y after the collision.

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#### Solution

According to the law of conservation of momentum, the two momenta given are equal to each other.

Before collision, momentum of the first ball is = (1)(2) = 2 kg.m/s

Before collision, momentum of the second ball = (1)(0) = 0

After collision, momentum of the first ball = (1)(0) = 0

After collision, momentum of the second ball is = (1)(v)

Now,

2 + 0 = 0 + 1v

⇒ v = 2

The velocity of Y after the collision is 2m/s.

Concept: Conservation of Momentum

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