A ball falls off a table and reaches the ground in 1 s. Assuming g = 10 m/s2, calculate its speed on reaching the ground and the height of the table.
Here, t =1 s
g = 10 m/s2
u = 0
Let v be the velocity of the ball on reaching the ground.
Thus, from first equation of motion, we have
v = u + gt
⇒ v = 10 x 1 = 10 m/s
Hence, the speed of the object on reaching the ground is 10 m/s.
Let h be the height of the table. Thus, from the second equation of motion, we have
`"S" = "ut" + 1/2 "gt"^2`
`⇒ "h" = 0 + 1/2 xx 10xx1^2`
⇒ h = 5 m
Hence, the height of the table is 5 m.