A bag contains twenty Rs 5 coins, fifty Rs 2 coins and thirty Re 1 coins. If it is equally likely that one of the coins will fall down when the bag is turned upside down, what is the probability that the coin:
will be a Re 1 coin?
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Solution
Total number of coins = 20+50+30=100
Total possible outcomes=100=n(S)
Number of favorable outcomes for Re 1 coins=30=n(s)
Probability (Re 1 coin)=`( n(E))/(n(S))=30/100=3/10 `
Concept: Probability - A Theoretical Approach
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