MCQ
A bag contains cards numbered from 1 to 25. A card is drawn at random from the bag. The probability that the number on this card is divisible by both 2 and 3 is
Options
\[\frac{1}{5}\]
\[\frac{3}{25}\]
\[\frac{4}{25}\]
\[\frac{2}{25}\]
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Solution
The total number of cards in the bag is 25.
∴ Total number of outcomes = 25
The numbers from 1 to 25 which are divisible by both 2 and 3 are 6, 12, 18 and 24.
So, the favourable number of outcomes are 4.
∴ P(number on the drawn card is divisible by both 2 and 3) = \[\frac{\text{ Favourable number of outcomes }}{\text{ Total number of outcomes }} = \frac{4}{25}\]
Concept: Basic Ideas of Probability
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