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A Bag Contains 6 Red, 4 White and 8 Blue Balls. If Three Balls Are Drawn at Random, Find the Probability that One is Red, One is White and One is Blue. - Mathematics

A bag contains 6 red, 4 white and 8 blue balls. if three balls are drawn at random, find the probability that one is red, one is white and one is blue.

 
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Solution

Total number of balls = 6 + 4 + 8 = 18
Total number of elementary events, n(S) = 18C3
Let E be the event of favourable outcomes.
Here, E = getting one red, one white and one blue ball
So, favourable number of elementary events, n(E) = 6C1 ×4C1 × 8C1
Hence, required probability = \[\frac{n\left( E \right)}{n\left( S \right)} = \frac{^{6}{}{C}_1 \times ^{4}{}{C}_1 \times^{8}{}{C}_1}{^{18}{}{C}_3}\]

\[= \frac{6 \times 4 \times 8}{\frac{18 \times 17 \times 16}{3 \times 2}}\]
\[ = \frac{6 \times 4 \times 8}{6 \times 17 \times 8}\]
\[ = \frac{4}{17}\]

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APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 33 Probability
Exercise 33.3 | Q 14 | Page 46
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