Question
A bag contains 16 colored balls. Six are green, 7 are red and 3 are white. A ball is chosen, without looking into the bag. Find the probability that the ball chosen is:
white or green
Solution
Balls in the bag =16= Number of balls that could be drawn
n(s)=16
E= Event of drawing a green or a white ball=number of green balls+number of white balls=6+3=9
n(E)=9
Probability of drawing a green or a white ball=`(n(E))/(n(s))=9/16`
Is there an error in this question or solution?
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A Bag Contains 16 Colored Balls. Six Are Green, 7 Are Red and 3 Are White. a Ball is Chosen, Without Looking into the Bag. Find the Probability that the Ball Chosen Is: White Or Green Concept: Simple Problems on Single Events.
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