A bag contains 10 red balls, 16 white balls and 8 green balls. A ball is drawn out of the bag at random. What is the probability that the ball drawn will be:
not red?
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Solution
Total number of possible outcomes = 10+16+8=34 balls
n(s)=34
Favorable outcomes for not a red ball= favourable outcomes for white or green ball
Number of favorable outcome for white or green ball=16+8=24=n(E)
Probability for not drawing a red ball =`(n(E))/(n(s))=24/34=12/17`
Concept: Simple Problems on Single Events
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