Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10th
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A and B are two events such that, P(A) = 0.42, P(B) = 0.48, and P(A ∩ B) = 0.16. Find P(A or B) - Mathematics

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Sum

A and B are two events such that, P(A) = 0.42, P(B) = 0.48, and P(A ∩ B) = 0.16. Find P(A or B)

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Solution

P(A) = 0.42 

P(B) = 0.48

P(A ∩ B) = 0.16

P(A or B) = P(A ∪ B)

= P(A) + P(B) – P(A ∩ B)

= 0.42 + 0.48 – 0.16

= 0.74

Concept: Addition Theorem of Probability
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APPEARS IN

Tamil Nadu Board Samacheer Kalvi Class 10th SSLC Mathematics Answers Guide
Chapter 8 Statistics and Probability
Exercise 8.4 | Q 2. (iii) | Page 330
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