A 4 Ω coil and a 2 Ω coil are connected in parallel. What is their combined resistance? A total current of 3 A passes through the coils. What current passes through the 2 Ω coil?

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#### Solution

The coils of the resistors of 4 Ω and 2 Ω are connected in parallel. Therefore:

`1/R=1/R_1+1/R_2`

`1/R=1/4+1/2`

`1/R=3/4`

`R=4/3`Ω

Combined resistance of the 4 Ω coil and the 2 Ω coil = 1.33 Ω

Total current = 3 A

The voltage across the whole cicuit,as in case of parallel circuit volatge is same scross all resistances.

V = IR.

V = 3 x 4/3 = 4 V

Therefore, the current through the 2 Ω coil,

I = V/R1.

I = 4/2 A

I = 2 A

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