Answer 1

`A(-4,2), B(0,2) and C(-2,-4)` are the vertioes of ΔABC,

`∴" Centroid of ΔABC"=((-4+0-2)/3,(2+2-4)/3)=((-6)/3,0/3)=(-2,0)`

P,Q and R are the mid-points of sides BC, CA and AB respectively. 

`∴ "Coordinates of P"= ((0-2)/2,(2-4)/2)=(-2/2,-2/2)=(-1,1)`

`∴" Coordinates of Q"= ((-2-4)/2,(-4+2)/2)=((-6)/2,(-2)/2)=(-3,-1)`

`∴ "Coordinates of R"=((-4+0)/2, (2+2)/2)=((-4)/2,4/2)=(-2,2)`

`∴ "Coordinates of ΔPQR"=((-1-3-2)/3,(-1-1+2)/3)=(-6/3,0/3)=(-2,0)`

⇒ Centroid of ΔABC=centroid of `ΔPQR`