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A 12 pF capacitor is connected to a 50 V battery. How much electrostatic energy is stored in the capacitor?

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#### Solution

Capacitor of the capacitance, C = 12 pF = 12 × 10^{−12 }F

Potential difference, V = 50 V

Electrostatic energy stored in the capacitor is given by the relation,

`"E" = 1/2 "CV"^2`

= `1/2 xx 12 xx 10^-12 xx (50)^2`

= `1.5 xx 10^-8 "J"`

Therefore, the electrostatic energy stored in the capacitor is `1.5 xx 10^-8 "J"`.

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