Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 11
Advertisement Remove all ads

7 X − 5 8 X + 3 > 4 - Mathematics

\[\frac{7x - 5}{8x + 3} > 4\]

Advertisement Remove all ads

Solution

We have, 

\[\frac{7x - 5}{8x + 3} > 4\]
\[ \Rightarrow \frac{7x - 5}{8x + 3} - 4 > 0\]
\[ \Rightarrow \frac{7x - 5 - 4\left( 8x + 3 \right)}{8x + 3} > 0\]
\[ \Rightarrow \frac{7x - 5 - 32x - 12}{8x + 3} > 0\]
\[ \Rightarrow \frac{- 25x - 17}{8x + 3} > 0\]
\[ \Rightarrow \frac{25x + 17}{8x + 3} < 0 (\text{ Multiplying by - 1 to make the coefficient of x in the LHS hspace{0.167em} positive })\]

\[x \in \left( \frac{- 17}{25}, \frac{- 3}{8} \right)\]

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 15 Linear Inequations
Exercise 15.1 | Q 27 | Page 10
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×