Advertisement Remove all ads

6 pipes are required to fill a tank in 1 hour 20 minutes. How long will it take if only 5 pipes of the same type are used? - Mathematics

Advertisement Remove all ads
Advertisement Remove all ads
Sum

6 pipes are required to fill a tank in 1 hour 20 minutes. How long will it take if only 5 pipes of the same type are used?

Advertisement Remove all ads

Solution

Let the desired time to fill the tank be x minutes. Thus, we have the following table.
Number of pipes 6 5
Time (in minutes) 80 x
Lesser the number of pipes more will be the time required by it to fill the tank. So, this is a case of inverse proportion.
Hence, 80 × 6 = x × 5.......[x1y1 = x2y2]
`(80 xx 6)/5 = x`
x = 96
Thus, time taken to fill the tank by 5 pipes is 96 minutes or 1 hour 36 minutes.
Concept: Concept of Inverse Proportion
  Is there an error in this question or solution?
Advertisement Remove all ads

Video TutorialsVIEW ALL [1]

Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×