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Sum

6 pipes are required to fill a tank in 1 hour 20 minutes. How long will it take if only 5 pipes of the same type are used?

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#### Solution

Let the desired time to fill the tank be x minutes. Thus, we have the following table.

Number of pipes |
6 | 5 |

Time (in minutes) |
80 | x |

Lesser the number of pipes more will be the time required by it to fill the tank. So, this is a case of inverse proportion.

Hence, 80 × 6 = x × 5.......[x

_{1}y_{1}= x_{2}y_{2}]`(80 xx 6)/5 = x`

x = 96

Thus, time taken to fill the tank by 5 pipes is 96 minutes or 1 hour 36 minutes.

Concept: Concept of Inverse Proportion

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