50 Cc of Oxygen is Collected in an Inverted Gas Jar Over Water. the Atmospheric Pressure is 99.4 Kpa and the Room Temperature is 27°C. the Water Level in the Jar is Same as the Level Outside. - Physics

Sum

50 cc of oxygen is collected in an inverted gas jar over water. The atmospheric pressure is 99.4 kPa and the room temperature is 27°C. The water level in the jar is same as the level outside. The saturation vapour pressure at 27°C is 3.4 kPa. Calculate the number of moles of oxygen collected in the jar.

Solution

Here ,

Atmospheric pressure, "P"_0 = 99.4 xx 10^3  "Pa"

SVP at 27^circ"C"  "P"_ω = 3.4 xx 10^3 "Pa"

T = 300K

V = 50 xx 10^-6"m"^3

Now,

Pressure inside the jar = Pressure outside the jar                                  [∵ Level of water is same inside and outside of the jar]

Pressure outside the jar = Atmospheric pressure

Pressure inside the jar = VP of oxygen + SVP of water at 27^circC

⇒ P_0 = P + Pω

⇒ P = P_0 - Pω = 99.4 xx 10^3 - 3.4 xx 10^3 = 96 xx 10^3

Applying equation of state , we get

PV = nRT

⇒ 96 xx 10^3 xx 50 xx 10^-6 = n xx 8.3 xx 300

⇒ n = 1.9277 xx 10^-3 "mol" ≈ 1.93 xx 10^-3 "mol"

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APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 2 Kinetic Theory of Gases
Q 56 | Page 37