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(3x - 2 y)^{3} + (2 y - 4z )^{3} + (4z - 3x)^{3}

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#### Solution

Let (3x - 2 y ) = a, (2 y - 4z ) = b, (4z - 3x) = c

∴ a + b + c = 3x - 2 y + 2 y - 4z + 4z - 3x = 0

∵ (3x - 2 y)^{3} + (2 y - 4z )^{3} + (4z - 3x)^{3}

∴ (3x - 2 y)^{3} + (2 y - 4z )^{3} + (4z - 3x)^{3} = 3(3x - 2y)(2y - 4z )(4z - 3x)

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