(2xy + 3y2) (3y2 − 2) - Mathematics

(2xy + 3y2) (3y2 − 2)

Solution

To multiply, we will use distributive law as follows:

$\left( 2xy + 3 y^2 \right)\left( 3 y^2 - 2 \right)$

$= 2xy\left( 3 y^2 - 2 \right) + 3 y^2 \left( 3 y^2 - 2 \right)$

$= 6x y^3 - 4xy + 9 y^4 - 6 y^2$

$= 9 y^4 + 6x y^3 - 6 y^2 - 4xy$

Thus, the answer is $9 y^4 + 6x y^3 - 6 y^2 - 4xy$.

Concept: Multiplication of Algebraic Expressions
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APPEARS IN

RD Sharma Class 8 Maths
Chapter 6 Algebraic Expressions and Identities
Exercise 6.5 | Q 16 | Page 31