Sum

25% of first order reaction is completed in 30 minutes. Calculate the time taken in minutes for the reaction to go to 90% completion.

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#### Solution

t = 30 min

[A]_{0} = 100

[A]_{1 = 75}

_{∴ `k = (2.303)/tlog [A]_0/[A]_1``therefore k = 2.303/30 log 100/75``therefore k = 0.076xx0.1249=9.58 xx 10^-3`Now, time requried for 90% completion t = ?}`[A]_0= 100`

`[A]_1 = 10`

k = 9.58 × 10^{-1 }_{}`9.58 × 10^-3 =2.303/t log 100/10 ` _{`t = 204.39 min`}

Concept: Meaning of Chemical Kinetics - Scope and Importance of Kinetics of the Reaction

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