# 2 Sec X + 3 Cot X − 4 Tan X - Mathematics

2 sec x + 3 cot x − 4 tan x

#### Solution

$\frac{d}{dx}\left( 2 sec x + 3 cot x - 4 \tan x \right)$
$= 2\frac{d}{dx}\left( \sec x \right) + 3\frac{d}{dx}\left( \cot x \right) - 4\frac{d}{dx}\left( \tan x \right)$
$= 2 \sec x \tan x - 3 \cos e c^2 x - 4 \sec^2 x$

Concept: The Concept of Derivative - Algebra of Derivative of Functions
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#### APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 30 Derivatives
Exercise 30.3 | Q 12 | Page 34