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2 cubes each of volume 64 cm^{3} are joined end to end. Find the surface area of the resulting cuboid.

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#### Solution

Given that,

Volume of cubes = 64 cm^{3}

(Edge)^{ 3} = 64

Edge = 4 cm

If cubes are joined end to end, the dimensions of the resulting cuboid will be 4 cm, 4 cm, 8 cm.

∴Surface area of cuboids = 2(lb+bh+lh)

= 2(4x4+4x8+4x8)

=2(16+32+32)

2(16+64)

=2x80 = 160 cm^{2}

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