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10 g of NaCl solution is mixed with 17 g of silver ni trate solution . Calculate the weight of silver chloride precipi tated. AgN03 + NaCl-; AgCI + NaN03 - Chemistry

Sum

10g of NaCl solution is mixed with 17g of silver nitrate solution. Calculate the weight of silver chloride precipitated.
AgNO3 + NaCl → AgCI + NaNO3

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Solution

Given reaction is :
AgNO3 + NaCl → AgCl + NaNO3
Molecular mass of AgNO3 is 170
Molecular mass of AgCI is 143.5
170g of AgNO3 produces = 143.5g of AgCl
17g of AgNO3 will produce = 143.5 x 17/170 = 14.35g
So, the weight of silver chloride precipitated is 14.35g

Concept: Relationship Between Vapour Density and Relative Molecular Mass
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APPEARS IN

Frank ICSE Class 10 Chemistry Part 2
Chapter 5 Mole Concept And Stoichiometry
Exercise | Q 15 | Page 116
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