# 10 balls are marked with digits 0 to 9. If four balls are selected with replacement. What is the probability that none is marked 0? - Mathematics and Statistics

Sum

10 balls are marked with digits 0 to 9. If four balls are selected with replacement. What is the probability that none is marked 0?

#### Solution

Let X denote the number of times of getting a ball marked with the digit 0.
P(getting a ball marked with the digit 0) = p = (1)/(10)

∴ q = 1 – p = 1 - (1)/(10) = (9)/(10)

Given, n = 4
∴  X ∼ B(4, 1/10)
The p.m.f. of X is given by

P(X = x) = ""^4"C"_x (1/10)^x (9/10)^(4 - x), x = 0, 1,...,4
P(none is marked with the digit 0) = P(X = 0)

= ""^4"C"_0 (1/10)^0 (9/10)^4

= (9/10)^4.

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#### APPEARS IN

Balbharati Mathematics and Statistics 2 (Commerce) 12th Standard HSC Maharashtra State Board
Chapter 8 Probability Distributions
Exercise 8.3 | Q 1.06 | Page 150