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Sum
1, 6, 11, 16 ...... Find the 18th term of this A.P.
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Solution
The given A.P. is 1, 6, 11, 16, ......
Here, a = 1, d = 6 – 1 = 5
Since tn = a + (n – 1)d,
t18 = 1 + (18 – 1)(5)
= 1 + 17(5)
= 1 + 85
= 86
∴ 18th term of the given A.P. is 86.
Concept: Arithmetic Progression
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