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Sum

1, 6, 11, 16 ...... Find the 18^{th} term of this A.P.

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#### Solution

The given A.P. is 1, 6, 11, 16, ......

Here, a = 1, d = 6 – 1 = 5

Since t_{n} = a + (n – 1)d,

t_{18} = 1 + (18 – 1)(5)

= 1 + 17(5)

= 1 + 85

= 86

∴ 18^{th} term of the given A.P. is 86.

Concept: Arithmetic Progression

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